As I've shown on picture that I attached:
∠ADC=∠ADB+∠BDC⇒134=5x+4+7x-2
12x+2=134
12x=132⇒x=132/12
x=11
Angle BDC measure 7x-2=7*11-2⇒∠BDC=75.
A.
(64x<span>² + 96x + 36) / (16x + 12)
= 4(16x</span><span>² + 24x + 9) / 4(4x + 3)
= 4*(4x + 3)(4x + 3) / 4(4x + 3)
= 4x + 3
b.
1.79 x 10^5 = 1.79 * 100,000 = 179,000
c.
(5.9736 x 10^24) + (4.8685 x 10^24)
= (5.9736 + 4.8685) x 10^24
= 10.8421 x 10^24
= 1.08421 x 10^25</span>
Answer:
19
Step-by-step explanation:
Answer:
4 inches
Step-by-step explanation:
The surface area, A of a right square pyramid is given by :
A = a² + 2as
Where, s = height of each triangular surface = x
a = base edge of pyramid
Substituting values into the equation :
A = 84 in² ; a = 6 in ; Slant height, s = x
84 = 6² + 2(6 * x)
84 = 36 + 2(6x)
84 = 36 + 12x
84 - 36 = 12x
48 = 12x
48/12 = 12x / 12
4 = x
Hence, Slant height, x = 4 inches
X + y = 12 . . . . . . . . (1)
x - 3y = -30 . . . . . . . (2)
(1) - (2): 4y = 42
y = 10.5
