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2 years ago

How can find the area

Mathematics

2 answers:

drek231 [11]2 years ago

8 0

If you add angle a and angle b, the answer is 180 degrees as it is a straight angle. So, to find what angle b is, you would subtract 11 from 180.

180 - 11 = 169

Therefore, angle b is 169 degrees

sashaice [31]2 years ago

6 0

180 - 11 = 169

So b = 169 degrees.

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Step-by-step explanation:

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3 years ago

Which of the following equations represents a line parallel to the line given by y=5x +9?

erma4kov [3.2K]

Answer:

y = 5x + 1

Step-by-step explanation:

Lines that are parallel to each other on a graph would have the same slope but different y-intercepts. When option A's equation is graphed along with the line given in the question, the lines appear to be parallel.

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3 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

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2 years ago

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Leokris [45]

It could possibly be one.

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3 years ago

I need help ASAP please (transforming functions)

Yuki888 [10]

Answer:

okay look at it this way:

Step-by-step explanation:

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(reflective)

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2 years ago

Read 2 more answers