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umka21 [38]
3 years ago
15

On Monday a company stock closed at a price of $30.80 per share. On Tuesday it increased by $1.20 per share. On Wednesday it fel

l by 6.25%. On Thursday it fell by another 4% and on Friday it increased by 2.5%. What is the net change in the stock price from Monday to Friday
Mathematics
2 answers:
fredd [130]3 years ago
5 0

Answer:

-1.28 on Plato

Step-by-step explanation:

aleksley [76]3 years ago
3 0
Tuesday:
30.80 + 1.20 = 32.00

Falling by 6.25% means it ends up being 93.75% of what it used to be (100% - 6.25% = 93.75%)

Wednesday:
32.00 * 0.9375 = 30

Thursday:
30 * 0.96 = 28.8

Friday:
28.8 * 1.025 = 29.52

Net change means you subtract to get the difference.

Net change = Final - initial
= 29.52 - 30.80
= -1.28

The stock fell $1.28
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kicyunya [14]
So hmm if you notice the picture below

between 2 and 16, there are 14 units, so, the center is half-way in between, thus, is at y = 7, or -2, 7

because, the major axis is over the y-axis, then the "a" component, goes under the fraction with the "y" in the numerator

\bf \textit{ellipse, vertical major axis}\\\\

\cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}, {{ k}}\pm a)\\\\
-----------------------------\\\\

\begin{cases}
b=4\\
a=7\\
h=-2\\
k=7
\end{cases}\implies \cfrac{(x+2)^2}{4^2}+\cfrac{(y-7)^2}{7^2}\implies \cfrac{(x+2)^2}{16}+\cfrac{(y-7)^2}{49}

8 0
3 years ago
A set of data has MAD O and one of the data values is 14. What can you say about the data values?
Alekssandra [29.7K]

Given:

Mean absolute deviation (MAD) = 0

One of the data values = 14.

To find:

The statement for other data values.

Solution:

We know that Mean absolute deviation (MAD) represents the average of absolute difference between observations and mean.

MAD=\dfrac{\sum |x_i-\overline x|}{n}

MAD is 0. It is possible if \sum |x_i-\overline x|. It means all the values of |x_i-\overline x| are 0.

It means no deviations in mean angle values and all the values are the same.

Therefore, if MAD is 0 and one data value is 14, then all the data values are same, i.e., 14.

8 0
3 years ago
A consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television set
puteri [66]

Answer:

The answer is "0.7794".

Step-by-step explanation:

Please find the complete question in the attached file.

Given:

\to n_{1}=n_{2}=25\\\\

Hypotheses:

\to H_{0}:\mu_{B}-\mu_{A}\geq 0\\\\\to H_{a}:\mu_{B}-\mu_{A}< 0\\\\

Testing statistics:

\to z=\frac{(\bar{x}_{B}-\bar{x}_{A})-(\mu_{B}-\mu_{A})}{\sqrt{\frac{\sigma^{2}_{B}}{n_{1}}+\frac{\sigma^{2}_{A}}{n_{2}}}}=\frac{3.5-(0)}{\sqrt{\frac{16^{2}}{25}+\frac{16^{2}}{25}}}=0.77

The test is done just so the p-value of a test is

\to p-value = P(z < 0.77) = 0.7794

Because the p-value of the management is large, type B can take it.

5 0
2 years ago
The function h(t) = 210 – 15t models the altitude of a hot air balloon over time t, in minutes.
Firdavs [7]
H(10)=210-15(10)
h(10)=210-150
h(10)=60

The hot air balloon is at an altitude of 210. The hot air balloon slowly falls 15 () per minute, for 10 minutes. He ends up at 60 altitude
6 0
2 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
strojnjashka [21]

Answer:

P(X = 3) = 0.14680064

Step-by-step explanation:

Formula=============================

p\left( X=k\right)  =C^{k}_{n}p^{k}(1-p)^{n-k}\ \ ;\ k\in \left\{ 0,\ldots ,n\right\}

……………………………………………………………………..

Given :

n = 8

p = 0.2

1 - p = 1 - 0.2 = 0.8

k = 3

Then

p\left( X=3\right)  =C^{3}_{8}(0.2)^{3}(0.8)^{5}

               =0.14680064

4 0
1 year ago
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