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3 years ago

A solid cylinder (1 =1/2mr2 ) with a mass of 4.83 kg and a radius of 0.057 m starts

Physics

1 answer:

netineya [11]3 years ago

3 0

Answer:

v = 7.32 m/s

Explanation:

The potential energy will convert to kinetic energy

½Iω² + ½mv² = mgh

Iω² + mv² = 2mgh

(½mR²)(v/R)² + mv² = 2mgh

½mv² + mv² = 2mgh

½v² + v² = 2gh

3v²/2 = 2gh

v² = 4gh/3

v² = 4(9.81)(4.10)/3

v² = 53.628

v = 7.323114...

v = 7.32 m/s

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A sample of nitrogen occupies 5.50 liters under a pressure of 900 torr at 25oC. At what temperature will it occupy 10.0 liters a

vitfil [10]

Answer:

<u>At 268.82°C</u> volume occupied by nitrogen is 10 liters at pressure of 900 torr.

Explanation:

Given:

Volume of a sample of nitrogen = 5.50 liters

Pressure = 900 torr

Temperature = 25°C

To find the temperature at which the nitrogen will occupy 10 liters volume at same pressure.

Solution:

Since the pressure is kept constant, so we can apply the temperature-volume law also called the Charles Law.

Charles Law states that the volume of a gas held at constant pressure is directly proportional to the temperature of the gas in Kelvin.

Thus, we have :

$V$ ∝ $T$

$\frac{V}{T}=k$

where $k$ is a constant.

For two samples of gases, the law can be given as:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

From the data given:

$V_1=5.5\ l$

$T_1=25\ \°C =(273+25)K= 298 K$

$V_2=10\ l$

We need to find $T_2$ .

Plugging in values in the formula.

$\frac{5.5}{298}=\frac{10}{T_2}$

Multiplying both sides by $T_2$ .

$T_2\times\frac{5.5}{298}=\frac{10}{T_2}\times T_2$

$\frac{5.5}{298}T_2={10}$

Multiplying both sides by $\frac{298}{5.5}$

$\frac{298}{5.5}\times\frac{5.5}{298}T_2=\frac{10\times 298}{5.5}$

$T_2=541.82\ K$

$T_2=541.82\ K-273\ K = 268.82\°C$

Thus, at 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.

7 0

3 years ago

Katrina’s recipe for orange muffins calls for 400 grams of flour. How many kilograms of flour are in the recipe?

aliina [53]

Answer:

0.4 Kilograms of flour

Explanation:

If you convert 400 grams into kilograms (400 ÷ 1,000), you would get 0.4 kilograms.

3 0

3 years ago

What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile

vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, $P=100\times 10^6\ N/m^2=10^8\ Pa$

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

$F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N$

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

4 0

4 years ago

If the star Alpha Centauri were moved to a distance 10 times farther than it is now, its parallax angle would

steposvetlana [31]

Answer:

B. get smaller

Explanation:

The parallax angle of a star measured with respect to the Earth is inversely proportional to the distance of the star from the Earth:

$\theta = \frac{1}{d}$

where

$\theta$ is the parallax angle, measured in arcsec

d is the distance between the star and the Earth, measured in parsec

Therefore, if the star Alpha Centauri is moved farther from Earth, then d increases, and therefore the parallax angle will get smaller.

3 0

3 years ago

How much time does it take a pulse of light to travel through 150 m of water?

jenyasd209 [6]

Answer:

6.65×10⁻⁷ s

Explanation:

Speed of light in water = Total distance traveled in water/time

c = d/t ....................... Equation 1

Where c = speed of the light pulse in water, d = distance traveled in water, t = time.

also

c = v/n ..................... Equation 2

Where v = speed of light in air, n = refractive index of water

Substituting equation 2 into equation 1

v/n = d/t

making t the subject of the equation,

t = nd/v.................. Equation 3

Given: 150 m.

Constant: n = 1.33, v = 3.0×10⁸ m/s

Substitute into equation 3

t = 1.33(150)/3.0×10⁸

t = 6.65×10⁻⁷ seconds.

Hence the time = 6.65×10⁻⁷ s

3 0

4 years ago