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Katarina [22]
4 years ago
7

What is the opposition to the flow of AC produced by a magnetic field with generated back voltage (EMF) called?

Physics
1 answer:
jek_recluse [69]4 years ago
5 0

Answer and Explanation :

The opposition of the flow of alternating current produced by a magnetic field is called inductive reactance it is denoted by X_L, The value of the inductive reactance depends on the value of inductance. The good thing about inductive reactance is that it is not responsible for the power loss as  resistance is responsible for the power loss  

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A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio
Julli [10]

Answer:

v_3 = 400\ m/s

Explanation:

given,

mass of the body = 40 Kg

speed in x-axis = 238 m/s

mass break into three part

m₁ = 7 kg

v₁ = 356 m/s (along the positive y axis)

m₂ = 4.5 kg

v₂ = 357 m/s(along the negative x axis)

m₃ = 40 - (7 + 4.5) = 28.5 Kg

v₃ = ?

using conservation of momentum

MV = m₁v₁ + m₂v₂ + m₃v₃

(40)(238) \hat{i} = (7)(356) \hat{j} - (4.5)(357) \hat {i} + 28.5 v_3

(9520) \hat{i} = 2492 \hat{j} - 1606.5\hat {i} + 28.5 v_3

11126.5 \hat{i} - 2492 \hat{j} = 28.5 v_3

v_3 =390.40 \hat{i} - 87.44 \hat{j}

v_3 = \sqrt{390.40^2 + 87.44^2}

v_3 = 400\ m/s

4 0
3 years ago
Identify and draw the forces that act on the pencil. Be certain to draw each force at the correct location (the point at which t
Alekssandra [29.7K]

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Explanation:

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What is the main difference between the gas water vapor and the liquid water?
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If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot
Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

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We need to calculate the moment of inertia

Using formula of moment of inertia

I=I_{1}+I_{2}

I=(m+m_{1})\times r^2+(m+m_{2})\times r^2

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2

I=117.45\ kg-m^2

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

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