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IgorLugansk [536]
3 years ago
5

You are designing a new piece of fishing equipment that will allow you to catch a fish from the surface. You know that water ref

racts light, but in order to properly program your device, you need to know by what angle water refracts light. Describe an experiment you would conduct to determine the angle at which water refracts light.
Please help! I’ll really appreciate it! :(
Physics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

Law of refraction

Explanation:

An experiment to analyze the refraction of light in water can easily be performed with a laser pointer and protractor.

We throw the fishing rod line into the water, place the protractor at the point where the line touches the water and use the direction of the line for the direction of the laser pointer (on), the laser is visible by the reflection on the particles in the air.

The vertical line is called Normal and all angles must be measured with respect to this reference in optics.

Having these angles and the refractive index of water we can use the law of refraction

         n₁ sin θ₁  = n₂ sin θ₂

         θ₂ = sin^{-1} ( \frac{n_1}{n_2} \ sin \ \theta_1 )

we can repeat several times to analyze several different input points (different angles) and to decrease the errors in the measurements.

the refractive index of air is n1 = 1 and n2= 1.33  (water)

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An object with a mass of 30 kg moves at a rate of 15 m/S over distance of 10 m. 900 joules of work was done in 10 seconds. What
Sliva [168]

Answer:

P = 90 W

Explanation:

Mass of an object, m = 30 kg

Speed of the object, v = 15 m/s

Distance, d = 10 m

Work done, W = 900 J

Time, t = 10 s

We need to find the power generated by this project. We know that power is equal to work done divided by time taken.

So,

P=\dfrac{W}{t}\\\\P=\dfrac{900\ J}{10\ s}\\\\P=90\ W

So, the required power generated is 90 W.

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3 years ago
Temperature is generally proportional to a substance's _______.
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rotational kinetic energy of it's particles

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4 years ago
1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?
Mila [183]

Answer:

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Explanation:

4 0
3 years ago
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At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
Tarik winds a small paper tube uniformly with 183 turns 183 turns of thin wire to form a solenoid. The tube's diameter is 9.49 m
Rufina [12.5K]
<h2>Answer:</h2>

143μH

<h2>Explanation:</h2>

The inductance (L) of a coil wire (e.g solenoid) is given by;

L = μ₀N²A / l                 --------------(i)

Where;

l = the length of the solenoid

A = cross-sectional area of the solenoid

N= number of turns of the solenoid

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

<em>From the question;</em>

N = 183 turns

l = 2.09cm = 0.0209m

diameter, d = 9.49mm = 0.00949m

<em>But;</em>

A = π d² / 4                     [Take π = 3.142 and substitute d = 0.00949m]

A = 3.142 x 0.00949² / 4

A = 7.1 x 10⁻⁵m²

<em>Substitute these values into equation (i) as follows;</em>

L = 4π x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209           [Take π = 3.142]

L = 4(3.142) x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209

L = 143 x 10⁻⁶ H

L = 143 μH

Therefore the inductance in microhenrys of the Tarik's solenoid is 143

6 0
3 years ago
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