Answer:
see below
Step-by-step explanation:
x = 63 and y = 27
180 - 117 Gives 63
No
Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.
Consider the 3 given sides 1, 7 and 11
7 + 11 = 18 > 1
1 + 11 = 12 > 7
1 + 7 < 11 ⇒ not valid
Hence these sides do not form a triangle
Hello from MrBillDoesMath!
Answer:
40
Discussion:
A diagram is always appreciated!
Assuming that
mAOC = mAOB + mBOC =>
108 = (3x + 4) + (8x - 28) => combine common terms
108 = (3x + 8x) + (4 - 28 ) =>
108 = 11x - 24 => add 24 to both sides
132 = 11x =>
x = 132/11 = 12
So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40
Thank you,
MrB
It would be 6 x 6 x 6, since the number cube has six sides and it was thrown 3 times.
5 because it appears most
Mode is most
