Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
73
Step-by-step explanation:
Answer:
y=-4x+3
Step-by-step explanation:
it does not show the equations that are following
but the main thing you need to know is that when two lines are parallel they have the same slope
and do you mean 2x+8y=18 not x?
edit:
answer choices: y=-4x+3, y=8x-2, y=4x+7, y=-8x+9
2y+8x=18
first change that equation to slope intercept form to find the slope
2y = -8x+18 -> y = -4x+9
slope is -4
so the answer is y=-4x+3 because it also has a slope of -4
Answer:
E) 1 and 2
Step-by-step explanation:
We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.
Thus:
n^(st) = 6^(2*3) = 6^6 = (2^6)(3^6)
For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)
For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6
For the third condition: s+t = 3+2 = 5 is not a factor of 6^6 or (2^6)(3^6)
Therefore, only 1 and 2 are factors of n^(st)
