3 years ago

In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15.

Mathematics

1 answer:

Advocard [28]3 years ago

3 0

What is the name of the parelellogram

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What is the product of (–6)2? (1 point) <br> a. –3 <br> b. –12 <br> c. 36 <br> d. 6

cupoosta [38]

(-6)2 means -6 x 2
which equals -12
B

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3 years ago

Which is the equation of a hyperbola centered at the origin with y-intercepts +12 -12, and asymptote y=3x/2

dangina [55]

Answer:

$\frac{y^2}{144}-\frac{x^2}{64}=1$

Step-by-step explanation:

The equation of a hyperbola centered at the origin with vertices on the y-axis is given by: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$

The vertices of the hyperbola are the y-intercepts (0,12) and (0,-12)

This implies that:

$2a=|12--12|$

$2a=24$

$a=12$

The asymptote equation of a hyperbola is given by:

$y=\pm\frac{a}{b}x$

The given hyperbola has asymptote: $y=\pm\frac{3}{2} x$

By comparison; $\frac{a}{b}=\frac{3}{2}$

$\implies \frac{12}{b}=\frac{12}{8}$

$\implies b=8$

The required equation is:

$\frac{y^2}{12^2}-\frac{x^2}{8^2}=1$

$\frac{y^2}{144}-\frac{x^2}{64}=1$

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Brilliant_brown [7]

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Step-by-step explanation:

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The answer would be > now u can give the other person brainliest!

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