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lozanna [386]
3 years ago
7

One pound equals approximately 454 grams. About how many grams is à pound?

Mathematics
2 answers:
Degger [83]3 years ago
4 0

Answer:

the answer is 453.592

Step-by-step explanation:

julsineya [31]3 years ago
3 0

Answer:

454 grams I believe..................

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Please help ill give brainliest if correct
yan [13]

Answer:

130

Step-by-step explanation:

ABC = 180 - 120 = 60

ACB = 180 - 70 - 60 = 50

ACD = 180 - 50 = 130

I hope I've helped you.

3 0
2 years ago
Name two angles that form a linear pair
Kay [80]

Answer:

Step-by-step explanation:parallel horizontal

7 0
3 years ago
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For each mile that Jason runs, Meagan runs 1/4 Mile farther. If Jason ran 6 miles,how far did Megan run ?
Darina [25.2K]
6/1 × 1/4 = 6/4
6/4 = 1 2/4 = 1 1/2
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8 0
3 years ago
50 points :] !!
nasty-shy [4]

Given,

LP = 15, PR = 9

Point P lies on the line segment PR. It would mean that,

LP + PR = LR

⇒LR = 15 + 9

⇒ LR = 24

Hence, "LR = 24 because LP + PR = LR according to the Segment Addition Postulate, and 15 + 9 = 24 using substitution" is the correct option.

6 0
3 years ago
A company considers buying a machine to manufacture a certain item. When tested, 28 out of 600 items produccd by the machine wer
weqwewe [10]

Answer:

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

Step-by-step explanation:

The null and alternate hypothesis are:

H0:p≥0.03

Ha:p<0.03

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis:

This means that \mu = 0.03, \sigma = \sqrt{0.03*0.97}

28 out of 600 items produced by the machine were found defective.

This means that n = 600, X = \frac{28}{600} = 0.0467

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.0467 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{600}}}

z = 2.4

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.0467, which is the p-value of z = 2.4.

Looking at the z-table, z = 2.4 has a p-value of 0.9918.

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

7 0
2 years ago
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