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Ne4ueva [31]
2 years ago
11

Evaluate the expression 5(8y+3r-5z) if r=3,y=5/8,and z=2

Mathematics
1 answer:
snow_lady [41]2 years ago
3 0
First you plug in the missing values
5(8×5/8+3×3-5×2) = 20
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NEED ANSWER ASAP PLEASE
lesya [120]

Answer:

FG=17/4  

Step-by-step explanation:

EF+FG=EG

3+x+3=5x+1

x+6=5x+1

6-1=5x-x

4x=5

x=5/4

FG=x+3

FG=5/4 +3

    = (5+12)/4

FG=17/4 or 4 1/4   or 4.25

4 0
2 years ago
How many times does 9 go into 777?
Neporo4naja [7]
777÷9=86.3 recurring
5 0
3 years ago
The test scores of 32 students are listed below. Construct a boxplot for the data set and include the values of the 5-number sum
zhenek [66]

Answer:

Boxplot is constructed using quartiles and 5 No. summary means including minimum value of data, 1st quartile, 2nd quartile, 3rd quartile and maximum value of data.

As data already in increasing order, we find quartiles using the following formula,

value\:of\:K_{th}\:Quartile\:,\, Q_k=\:value\:of\:(\frac{k\times{(n+1)}}{4})\,\:th\,observation

where n = No. of Observations.

∴, 1st Quartile,

Q_1 = \frac{1\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=8.25\,th\:observation\\\: \:\:= 8th\,+0.25(9th-8th)\\\:\:\:= 55 + 0.25(57-55)\\\:\:\:= 55.5

2nd Quartile,

Q_2 = \frac{2\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=16.5\,th\:observation\\\: \:\:= 16th\,+0.5(17th-16th)\\\:\:\:= 69 + 0.5(70-69)\\\:\:\:= 69.5

3rd Quartile,

Q_3 = \frac{3\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=24.75\,th\:observation\\\: \:\:= 24th\,+0.75(25th-24th)\\\:\:\:= 79 + 0.75(81-79)\\\:\:\:= 80.5

Minimum value of data = 32 & Maximum value of data = 99

So, Values of 5 no. that are to ne include in Boxplot are 32, 55.5, 69.5, 80.5, 99.

BoxPlot is attached with this ans.

7 0
2 years ago
Not quite sure how to find out if these are functions or not
iVinArrow [24]

number 5 is not and number 7 is a function because every input has exactly one output

3 0
3 years ago
Determine the y-intercept of the linear
Anna [14]

Answer:

The y-intercept is 0

Step-by-step explanation:

7 0
2 years ago
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