Make COS the subject of the formula
1 answer:
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For this case, the first thing we are going to do is assume that all the tests are worth the same.
Then, we define a variable:
x: score of Mona's last test
We write now the inequality that models the problem:
From here, we clear the value of x:
Answer:
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
x = 87
Then, we define a variable:
x: score of Mona's last test
We write now the inequality that models the problem:
From here, we clear the value of x:
Answer:
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
x = 87
Answer:
The functions satisfy the differential equation and linearly independent since W(x)≠0
Therefore the general solution is
Step-by-step explanation:
Given equation is
This Euler Cauchy type differential equation.
So, we can let
Differentiate with respect to x
Again differentiate with respect to x
Putting the value of y, y' and y'' in the differential equation
⇒m²-10m +24=0
⇒m²-6m -4m+24=0
⇒m(m-6)-4(m-6)=0
⇒(m-6)(m-4)=0
⇒m = 6,4
Therefore the auxiliary equation has two distinct and unequal root.
The general solution of this equation is
and
First we compute the Wronskian
=x⁴×6x⁵- x⁶×4x³
=6x⁹-4x⁹
=2x⁹
≠0
The functions satisfy the differential equation and linearly independent since W(x)≠0
Therefore the general solution is