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Iteru [2.4K]
3 years ago
7

A country is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30

miles per hour. A random sample of 15 vehicles has a mean speed of 35 miles per hour and a standard deviation of 4.7 miles per hour. At ? = .01, do you have enough evidence to supprot the country's claim?
Calculate the p-value:
Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

We conclude that speed is greater than 30 miles per hour.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ =  30 miles per hour

Sample mean, \bar{x} = 35 miles per hour

Sample size, n = 15

Alpha, α = 0.01

Sample standard deviation, s = 4.7 miles per hour

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30\text{ miles per hour}\\H_A: \mu > 30\text{ miles per hour}

We use one-tailed(right) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{35 - 30}{\frac{4.7}{\sqrt{15}} } = 4.120

Now, t_{critical} \text{ at 0.01 level of significance, 14 degree of freedom } = 2.624

Since,                  

t_{stat} > t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis and conclude that speed is greater than 30 miles per hour.

We calculate the p-value.

P-value = 0.00052

Since p value is lower than the significance level, we reject the null hypothesis and accept the alternate hypothesis. We conclude that speed is greater than 30 miles per hour.

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Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

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- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

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- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

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- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

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* Lets solve the problem

- There are two triangles TUW and VWU

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- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

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- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

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