A Skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 25°. The force applied to the skier b
y the tow bar is parallel to the slope. The skier's mass is 55.0 kg and the coefficient of kinetic friction between the skies and snow is 0.12. Find the magnitude of the force that the tow bars exert on the skier.
To solve your problem, we can apply Newton's second law of motion. Fⁿ = ma
<span>Fnet = net force acting on the skier </span> <span>m = mass of the skier = 53 kg </span> <span>a = acceleration up the slope </span>
<span>Since velocity is constant then acceleration is zero, hence the above equation becomes </span>
<span>Fnet = 0 </span>
<span>Fnet = F - Wx - f </span>
<span>where </span>
<span>F = force exerted by the tow bar </span> <span>Wx = component of skier's weight parallel to the incline = 53(9.8)(sin 20) </span> <span>f = frictional force = 0.160(53)(9.8)(cos 20) </span>
