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Deffense [45]
3 years ago
13

What is the value of the expression ?

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

The value of this expression is 3 x 10^{6}


In order to find this, you divide each term separately. First we'll start with the numbers in the front.


\frac{4.8}{1.6} = 3


Now that we have the first number, we look to the 10s and the powers they are raised to. Since we are looking at powers of the same number, we can use the properties of exponents to simply subtract the numbers they are raised to.


\frac{10^{9}}{10^{3}}  = 10^{6}


Then we put the two back together for the final answer.


3 x 10^{6}

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2. Ms.A buys 7 boxes of snacks. Each box has 12 packets of fruit snacks and 18 packets of cashews.
timurjin [86]

Answer:  210

Explanation:

Each box has 12 packets of fruit snacks and 18 packets of cashews. That gives 12+18 = 30 packets overall per box. Since we have 7 boxes, that tells us the total count is 7*30 = 210

6 0
3 years ago
Read 2 more answers
An artist buys 36 tubes of oil paint, 6 paintbrushes, 3 canvases, and 2 jars of paint thinner. What is the ratio of paintbrushes
IgorLugansk [536]
D) 1:6 because she brought 6 paintbrushes and 36 tubes of oil paint, and we can simplify that to 1/6
8 0
3 years ago
Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y
castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Fail the test.
  • Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

  • 46% of 37%(are fit).
  • 100% of 63%(not fit).

Hence:

P(A) = 0.46(0.37) + 0.63 = 0.8002

The probability of both failing the test and being unfit is:

P(A \cap B) = 0.63

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0
3 years ago
Find the value of x.
Veseljchak [2.6K]
<h3>Answer:  x = 35  (choice D)</h3>

====================================================

Work Shown:

secant angle = (far arc - near arc)/2

angle BGC = (arc BC - arc AD)/2

40 = (115 - x)/2

2*40 = 115-x

80 = 115-x

115-x = 80

-x = 80-115

-x = -35

x = 35

For more information, you can search out "secant angles" and it should go over how the formula is set up and why it works.

4 0
3 years ago
A net of a three-dimensional figure is shown. What is the surface area of the three-dimensional figure?
deff fn [24]

Answer:

184 ft^2

Step-by-step explanation:

in the picture

7 0
3 years ago
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