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ElenaW [278]
3 years ago
11

Calculate m∠ADC. Round to the nearest thousandth.

Mathematics
1 answer:
stira [4]3 years ago
4 0

Answer:  54.508^{\circ}

Step-by-step explanation:

Let the angle ADC = x degree

Since, By the given diagram, In triangle BDC,

\frac{BC}{DC} = tan27^{\circ}

⇒ \frac{BC}{19.6} = tan27^{\circ}

⇒ BC = 19.6\times tan 27^{\circ}

⇒  BC = 9.98669881009

Now, In triangle ADC,

tan x =\frac{AC}{DC}

⇒  tan x =\frac{AB+BC}{DC}

⇒  tan x =\frac{17.5+9.98669881009}{19.6}

⇒  tan x =\frac{27.4866988101}{19.6}

⇒  tan x =1.40238259235

⇒  x = 54.508389368\text{ degree} \approx 54.508^{\circ}

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Express p/q form of 10.03636......
Crank

Let's assume x= 10.03636........ (1)

Multiply each sides by 100. So,

100x = 1003.63636.......... (2)

Next step is to subtract the equation (1) and (2)

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weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
4 years ago
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