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Vilka [71]
2 years ago
14

2. What is the variable in the expression: 13x3 +7 (Select one answer) 7 3 13

Mathematics
1 answer:
sdas [7]2 years ago
3 0
I think it would be 3
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Jenica has $4.50 in dimes and quarters. She has 1 more than three as many quarters as dimes. How many quarters does she have?
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Answer:

Laura has $4.50 in dimes and quarters she has 3 more dimes than quarters How many quarters does she have

She has 3 more dimes than quarters. How many quarters does she have? Laura has 15 dimes and 12 quarters.

Step-by-step explanation:

4 0
3 years ago
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#19 solve the equation. 5m + 4m = 72
Ganezh [65]
5m + 4m = 72

Combine like terms.

9m = 72

Divide both sides by 9.

m = 8
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You are trying to hack into your mom's computer. You know your password is 4 letters and then a number but you can not remember
podryga [215]
The amount of passwords you can guess are 4,569,760. 
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7 0
3 years ago
Can someone tell me what I did wrong here
Soloha48 [4]

Answer:

no roots.

Step-by-step explanation:

1)   \sqrt{8x+16}=2-8; \ - \ correct;

2)   \sqrt{8x+16}=-6; \ - \ correct;

note, the value after operation 'square root' cannot be negative ('-6' is on the right side!), then

3) it means, the given equation has no real roots.

8 0
2 years ago
A trader bought x mangoes at the rate of 4 mangoes for 10 naira five of the mangoes were bad so he sold the remaining at the rat
Ilya [14]

Answer:

20 mangoes.

Step-by-step explanation:

Given:

Total  number of mangoes, a trader bought = x

A trader bought at the rate of 4 mangoes for 10 naira.

Five of the mangoes were bad.

He sold the remaining at the rate of 5 mangoes for 20 naira.

He made a gain of 10 naira

Question asked:

Total  number of mangoes, a trader bought = x = ?

Solution:

Unitary method

Cost price of  4 mangoes =  10 naira.

Cost price of  1 mango = \frac{10}{4}

Cost price of x mango = \frac{10}{4}\times x= \frac{5}{2} x

As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold =  x-5

Sale price of 5 mangoes = 20 naira

Sale price of 1 mango = \frac{20}{5}

Sale price x-5 of mango = \frac{20}{5}\times(x-5)=4(x-5)=4x-20

Now, as we know,

Gain = Sale price - cost price

10 = 4x-20 -\frac{5}{2} x\\ 10=4x-\frac{5}{2} x-20\\10=\frac{8x-5x}{2} -20

10 =\frac{3x}{2} -20

Adding both sides by 20

30=\frac{3x}{2}

Multiplying both sides by 2

60 = 3x

Dividing both sides by 3

x=20

Therefore, total number of mangoes, a trader bought is 20.

3 0
3 years ago
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