3 years ago

Please help i will mark brainly

Mathematics

1 answer:

OverLord2011 [107]3 years ago

5 0

The answer:

Is d have a good day

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A study of the career paths of hotel general managers sent questionnaires to an SRS of 280 hotels belonging to major U.S. hotel

const2013 [10]

Answer and Step-by-step explanation:

we have the following data:

Point estimate = sample mean = \ bar x = 12.39

Population standard deviation = \ sigma = 3.7

Sample size = n = 177

a) the margin of error with a 90% confidence interval

α = 1 - 90%

alpha = 1 - 0.90 = 0.10

alpha / 2 = 0.05

Z \ alpha / 2 = Z0.05 = 1,645

Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)

we replace:

E = 1.645 * (3.7 / \ sqrt177)

Outcome:

E = 0.46

b) margin of error with a 99% confidence interval

α = 1-99%

alpha = 1 - 0.99 = 0.01

alpha / 2 = 0.005

Z \ alpha / 2 = Z0.005 = 2,576

Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)

we replace:

E = 2,576 * (3.7 / \ sqrt177)

Outcome:

E = 0.72

c) A larger confidence interval value will increase the margin of error.

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