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zysi [14]
3 years ago
13

Find the exact roots of x^2+10x-8=0 by completing the square

Mathematics
1 answer:
irinina [24]3 years ago
5 0
From the original equation x^2+10x-8=0, move the loose number on the other side. Your new equation will be x^2+10x=8. Moving an element from one side to another reverses its sign. From -8 to +8. Then take half of the x-term and square it and add it on both sides. X-term is 10x and 10 is the number, half of it is 5 then square of 5 is 25. Add 25 on both side. Your new equation will be x^2+10x+25=8+25. Then complete the square form of the left side of the equation, (x+5)^2=33. Square root both side then you will get x+5=squareroot of 33. Your x = -5 plus/minus squareroot of 33.
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6 0
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Here's a better picture
schepotkina [342]
1) 3/5=9/x (cross multiply<span>)
3x=5(9)
3x=45
x=15

2) </span>2/4=x/12   (cross multiply<span>)
</span> 2(12)=4x
     24=4x
<span>       6=x

</span>3) 10/x=5/9   (cross multiply<span>)
   10(9)=5x
       90=5x
       18=x
</span>
4) 5/6=x/18
5(18)=6x
90=6x
x=15
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