Answer:

Step-by-step explanation:
This is a hard one
We have to use the rational root theorem
= 0
We have to find all the factors of a and d and put them in a fraction

We then plug them into the equation to see if any of them work
The equation isn't true when plugging 1, but is true when plugging in 1/2
factored form of 1/2 is (2x-1)
Then we divide the original equation by (2x-1) (you can use synthetic division or long division, it would be hard to type out the process for that) to get 
So now the equation is 
Solve the second half of this equation using the quadratic formula to get
and 
We already know the solution for the first half of the equation (1/2)
So the final answers are:

Answer:
39/80
Step-by-step explanation:
0 and 5 can be in the one's place of a number that has 5 as a factor.