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Tatiana [17]
3 years ago
6

The balance in a bank account after t years is given by the equation B = 2500(1.015)

Mathematics
1 answer:
melomori [17]3 years ago
7 0
The answer to you question is b = 2537.5 I think
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What are the domain and range of f(x) = |x – 3 | + 6? Domain: {x | x is all real numbers} Range: {y | y ≥ 6} Domain: {x | x ≥ 3}
VARVARA [1.3K]

Answer:

Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.

Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.

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3 years ago
Each side of a square is increased by 3 inches. The perimeter of the new square is 40 inches more than twice the length of the s
RUDIKE [14]

Length of side of new square is 17 inches

Step-by-step explanation:

  • Step 1: Let the length of the side of the old square be x. Then length of side of new square = x + 3 and Perimeter of new square = 40 + 2x

Perimeter of a square = 4 × side

⇒ 4(x + 3) = 40 + 2x

⇒ 4x + 12 = 40 + 2x

⇒ 2x = 28

⇒ x = 14 inches

  • Step 2: Find length of side of the new square

⇒ x + 3 = 17 inches

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3 years ago
A grading scale is set up for 1000 students' test scores. It assumes the
astra-53 [7]

Answer:

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

It assumes the scores are normally distributed with a mean score of 75 and a standard deviation of 15.

This means that \mu = 75, \sigma = 15

How many students will score between 48 and 75?

First we find the proportion, which is the pvalue of Z when X = 75 subtracted by the pvalue of Z when X = 48. So

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 75}{15}

Z = 0

Z = 0 has a p-value of 0.5

X = 48

Z = \frac{X - \mu}{\sigma}

Z = \frac{48 - 75}{15}

Z = -1.8

Z = -1.8 has a p-value of 0.0359

1 - 0.0359 = 0.4641

Out of 1000:

0.4641*1000 = 464

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

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