Answer:
The temperature of silver increase by 23.15 °C.
Explanation:
Given data:
Heat added = 155 j
Mass of silver = 27.9 g
How many degree temperature increase = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of silver is = 0.240 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
155 j = 27.9 g × 0.240 j/g.°C × ΔT
155 j = 6.696 j/°C × ΔT
ΔT = 155 j /6.696 j/°C
ΔT = 23.15 °C
Drexel’s it then u get the answer
Number of moles required to neutralize the solution=0.0354×0.0997
=0.0035mol
2 mol of NaOH required to neutralize 1 mol of diprotic acid.
So moles of acid 0.0035/2=0.0017
Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid
0.0017 =0.3041/Molar mass of diprotic acid
Molar mass of diprotic acid=0.3041/0.0017
=178.8 g/mol
Specific gravity = (density of substance)/(density of water)
= (1.18 g/mL)/(1.00 g/mL) = 1.18
Answer:
HBr + Mg(OH)2 —> MgBr2 + H2O.
To balance the above, we must do a head count of the individual atoms present to ensure they balance on both sides of the equation. To get the balance equation, add 2 in front of HBr and 2 in front of H2O as shown below:
2HBr + Mg(OH)2 —> MgBr2 + 2H2O
We can see clearly that the numbers of the individual atoms on the left side is the same on the right side
