The grams of sodium chloride that will be made is 292.5 g
<u><em>calculation</em></u>
2Na +Cl₂ → 2NaCl
step 1: calculate the moles of Na
moles = mass/molar mass
From periodic table the molar mass of Na = 23 g/mol
moles = 115 g/23 g /mol = 5 moles
Step 2 : use the mole ratio to determine the moles of NaCl
Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also= 5 moles
Step 3: find the mass of NaCl
mass= moles x molar mass
The molar mass of NaCl = 23 + 35 .5 =58.5 g/mol
mass= 5 moles x 58.5 g/mol =292.5 g
The answer is covalent bonding feel free to message me if you want to understand why this is the correct answer :)
The answer is (3) Mg because Ca and Mg are in the same group (group 2).
Hope this helps~
Answer:
B. The time during which a collision between two molecules occurs is negligibly short compared to the time between collisions
Explanation:
Kinetic molecular theory postulates:-
- The gas is composed of small molecules are they are in continuous random motion and having elastic collisions with one another and also with the walls of the container.
- The molecules of the gas does not exert any kind of repulsive or attractive forces on each other and they their size is negligible as compared to the difference between them.
- Pressure exerted by the molecules of the gas results from the collisions which is happening between the molecules of the gas and the walls of the container.
- Average kinetic energy of molecules of the gas is directly proportional to absolute temperature.
Hence, The correct option is:- <u>B. The time during which a collision between two molecules occurs is negligibly short compared to the time between collisions. This is not an important postulate of the kinetic molecular theory.</u>
Considering the equation,
3Na₂SO₄(aq)+2Al(NO₃)₃(aq)------>Al₂(SO₄)₃(s)+6NaNO₃(aq)
As it can be seen from the equation,
2 moles of Al(NO₃)₃ reacts with 3 moles of Na₂SO₄ to give 1 mol of Al₂(SO₄)₃.
Here 690 mL of 2.5 M Al(NO₃)₃=2.5× 690/1000
=1.7 mol of Al(NO₃)₃
As 2 moles of Al(NO₃)₃ give 1 mol of Al₂(SO₄)₃
So 1.7 mol of Al(NO₃)₃ give 1.7/2 mol of Al₂(SO₄)₃
so it will give 0.86 mol of Al₂(SO₄)₃.
Moles=mass given /molar mass
molar mass of Al₂(SO₄)₃= 342.1509 g/mol
Moles= mass given/342.1509
0.86=mass given/342.1509
mass of Al₂(SO₄)₃=295.1 g
so 295.1 g of Al₂(SO₄)₃ will be produced.
