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kap26 [50]
3 years ago
8

A) how many 3/5s are in 1 b) use the answer to part A to find the number of 3/5s in 2

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0
a)\frac{1}{\frac{3}{5}}=1*\frac{5}{3}=\frac{5}{3}\\\\
There\ are\ 1\frac{2}{3}\ of\ \frac{3}{5}s\ in\ 1.\\\\
b)\frac{2}{\frac{3}{5}}=2*\frac{5}{3}=\frac{10}{3}\\\\There\ are\ 3\frac{1}{3}\ of\ \frac{3}{5}s\ in\ 2.
Amiraneli [1.4K]3 years ago
5 0
3/5*n=1

Therefore n=5/3=3/3+2/3=1+2/3

----------------------------

3/5*x=2

3x=10

x=10/3=9/3+1/3=3+1/3
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Two consecutive even integers have a sum of 14. The equation that would be used to solve this
Over [174]
X + x + 2 = 14
2x + 2 = 14
2x = 12, x = 6
Solution: the smallest of the two integers is 6
5 0
3 years ago
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HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!
rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

3 0
3 years ago
A rectangle has perimeter 182 in. and length 52 in. What is the width
Degger [83]

Answer:

the width is 3.5 in.

Step-by-step explanation:

u get it by dividing 182 in and 52 in and u get 3.5 In

4 0
2 years ago
Read 2 more answers
One and a half x + 3/4 x equals 5/8
USPshnik [31]
1 and 1/2x+3/4x=5/8
combine x's
1 and 1/2x=4/4x+2/4x=6/4x
6/4x+3/4x=5/8=9/4x
9/4x=5/8
multiply both sides by 8
18x=5
x=5/18

x=5/18 or aprox 0.277777777777

5 0
3 years ago
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enelope determined the solutions of the quadratic function by completing the square. f(x) = 4x2 + 8x + 1 –1 = 4x2 + 8x –1 = 4(x2
Marat540 [252]
The correct question is
<span>Penelope determined the solutions of the quadratic function by completing the square.
f(x) = 4x² + 8x + 1
–1 = 4x² + 8x
–1 = 4(x² + 2x)
–1 + 1 = 4(x² + 2x + 1)
0 = 4(x + 2)²
0 = (x + 2)²
0 = x + 2
–2 = x
What error did Penelope make in her work?

we have that
</span>f(x) = 4x² + 8x + 1
to find the solutions of the quadratic function
let
f(x)=0
 4x² + 8x + 1=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

 (4x² + 8x)=-1

Factor the leading coefficient 

 4*(x² + 2x)=-1

Complete the square Remember to balance the equation by adding the same constants to each side.

 4*(x² + 2x+1)=-1+4 --------> ( added 4 to both sides)

Rewrite as perfect squares

4*(x+1)²=3

(x+1)²=3/4--------> (+/-)[x+1]=√3/2

(+)[x+1]=√3/2---> x1=(√3/2)-1----> x1=(√3-2)/2

(-)[x+1]=√3/2----> x2=(-2-√3)/2

therefore

the answer is

<span>Penelope should have added 4 to both sides instead of adding 1.</span>
6 0
3 years ago
Read 2 more answers
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