Answer:
assuming that you have solve x, the the answer is x=-16.6 repeating
Step-by-step explanation:
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
3/4 since (9 1/2 = length* width with makes the base) and divide it by 7 1/8.<span />
Answer:
26
Step-by-step explanation:
5x+6y
substitute x=16 and y=-9:
5*16+6*(-9)
=80-54
=26