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ioda
3 years ago
12

I really need help with these questions, 5 STARS AND BRAINLIEST FOR WHOEVER HAS THE BEET ANSWER!!

Mathematics
1 answer:
zvonat [6]3 years ago
5 0
1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2

Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept  x, (4/7,0)

Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2 
and so intercept  y, (0,-2)

Now you will follow the same logic to find the are same questions

2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3

3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5

4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1

5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8  & intercept y=2

6) x=5, this ligne is // to y axis at x=-5


 
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You finally get an allowance! You put $2.00 away in January, $4.00 away in February, $8.00 away in March, $16.00 away in April a
LekaFEV [45]

Answer:

$8190

Step-by-step explanation:

So we know that were putting away $2 each month from  our allowance.

Jan-$2

Feb-$4

March-$8

April-$16

Ok so we already put away 4 months of our allowance from 12. So we need 8 more months to count how much.

So lets add: 2 + 4 + 8 + 16=30

Now we need to figure out how much in May and so on.

May- 16x2=32

June-32x2=64

July-64x2=128

August-128 x 2=256

September-256 x 2=512

October-512 x 2=1024

November-1024 x 2=2048

December-2048 x 2=4096

In total to add:

2 + 4 + 8 + 16 + 32 +64 + 128 + 256 + 512 + 1024 + 2048 + 4096 = 8190

Hope this helps :)

3 0
3 years ago
0.701 rounding up to the nearest whole<br> Number. 5th grade
pentagon [3]

Answer:

If rounding up it is 1

Step-by-step explanation:

the nearest whole number is 1.

8 0
3 years ago
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Tell whether the indicated angles are adjacent.
Semenov [28]

Answer: 3 would be a adjacent angle

Step-by-step explanation:

They don’t overlap

4 0
3 years ago
X⋅x⋅x⋅x⋅x⋅(−3)⋅(−3)⋅(−3)
poizon [28]

Answer:

Hey mate, please describe your question perfectly.

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We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
3 years ago
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