Answer:
Average weight of the bags of potatoes is 3.8 pounds.
Step-by-step explanation:
Given:
Weight of the first bag, 
pounds.
Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,
Weight of the third bag is 0.6 pounds more than that of the first bag. This means,
Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,
Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,
Therefore, average weight of the bags of potatoes is 3.8 pounds.
The answer is 3 (x+b) (x-2)
Yw! :)
It can be 8:12 or as a fraction it’s 8/12
Hey there!
If we use pemdas:
P - Parentheses
E - Exponents
M - Multiplicatiom
D - Division
A - Addition
S - Subtractiom
We know we have to evaluate the exponent first. Two to the rid power is equal to 8. Therefore, we have:
2 - 4/2 + 8
Next, we do the division. -4/2 = -2, so we have:
2-2 + 8 = 0 + 8 = 8
Hope this helps!
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.
