Answer:
system of equations
Step-by-step explanation:
You can eliminate one of the variable terms in a <u>system of equations</u> by adding or subtracting another equation.
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Answer:
the formula is VAT %op cp ×13500 do that using this formul6 is should correct
Answer:
x=12 ADB= 56 BDC= 54
Step-by-step explanation:
ADB and BDC are complementary, so they add up to 90 degrees. In other words ADB+BDC= 90 So I can input my knowns into the equation
(3x+10) + (4x-4) = 90
I combined like terms to give me 7x+6=90
Then I subtract 6 from both sides giving me 7x=84
Last I divide 7 on both sides. x=12
Then I input the x (12) into the equation and solve it from there
3(12)+10 and 4(12)-4
3(12)+10=56
4(12)-4=54
. . . I think. Hope this helps!