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3 years ago

Will mark right answer brainliest!

Mathematics

1 answer:

Georgia [21]3 years ago

5 0

Answer:

1/12

Step-by-step explanation:

3/4 + -2/3

Get a common denominator of 12

3/4 *3/3 - 2/3 *4/4

9/12 - 8/12

1/12

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Membership to two different clubs are represented by the equations below. The x-value represents the number of months dues are p

mestny [16]

It would take 2 months for the membership of both clubs to be the same

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two numbers and variables.

The standard form of a linear equation is:

y = mx + b

Where m is the rate of change and b is the y intercept

Let y represent the total cost of dues over x months, hence given that:

y = 3x - 5 (1)

Also:

4x - 3y = 5

y = (4x - 5)/3 (2)

For the membership of both clubs to be the same:

3x - 5 = (4x - 5)/3

9x - 15 = 4x - 5

x = 2

It would take 2 months for the membership of both clubs to be the same

Find out more on equation at: brainly.com/question/2972832

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7 0

2 years ago

What is the answer to h -13h+-38=27

riadik2000 [5.3K]

-13h + -38 = 27
You have to have all the h alone and in the same side.
-13h=65
You have to divide -13h by -13 to find one h
h = -5

3 0

4 years ago

Read 2 more answers

I NEED HELP ASAP WILL GIVE BRAINLIEST FOR ALL 3

Viefleur [7K]

2) i don't know answer for 2, but i know that it isn't right triangle because from Pythagoras' Theory we know that for right triangle: a^2 + b^2 = c^2 but in this triangle 30^2 + 38^2 ≠ 54^2

3) from Pythagoras' theory we know that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides: a^2 + b^2 = c^2

we have to check this in this triangle:

12^2 + 16^2 = 400

√400 = 20

we know that third side of this triangle is 20 so this triangle is right triangle

3) in square all sides are same so If a is the one side of the square then area of this square will be a x a = 242

a^2 = 242

so from Pythagoras' theorem we can found the diagonal:

a^2 + a^2 = c^2 ( c is hypothenuse)

242 + 242 = c^2

484 = c^2

c = 22

hope it's correct and it'll help you :)

8 0

3 years ago

What are the coordinates of the center of the circle whose equation is x^2+y^2-16x+6y+53=0?

makkiz [27]

Hello :
<span>note :
an equation of the circle Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : </span><span>x²+y²-16x+6y+53=0
(</span>x²-16x) +( y²+6y ) +53 = 0
(x² -2(8)x +8² - 8²) +(y² +2(3)x -3²+3² ) +53=0
(x² -2(8)x +8²) - 8² +(y² +2(3)x +3²)-3² +53=0
(x-8)² +( y+3)² = 20

the center is : w(8,-3) and ridus : r = <span>√20</span>

8 0

3 years ago

The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax

charle [14.2K]

First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

$\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx$

Let $u=e^x$ , so that $\mathrm dx=\dfrac{\mathrm du}u$ , and the integral is equivalent to

$\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du$

The integrand is continuous everywhere except $u=0$ , but that's okay because we have $\lim\limits_{u\to0^+}\frac{\sin u}u=1$ . This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

$\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx$

By the same substitution as before, we can write this as

$\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du$

The half-angle identity for sine allows us to rewrite as

$\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du$

and replacing $v=2u$ , $\dfrac{\mathrm dv}2=\mathrm du$ , we have

$\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv$

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

$\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))$

where $\gamma$ is the Euler-Mascheroni constant and $\mbox{Ci}$ denotes the cosine integral function.

5 0

4 years ago