0.76 is the answer
hope this helped
Answer:
The acceleration in the system and in the rope is same as 5.88 m/s2.
Step-by-step explanation:
The figure shows two blocks of m1 = 0.8 Kg and m2 = 0.2 kg if the block of mass m2 is dragged by the block of mass m1 calculate the acceleration of the system and the acceleration of the rope
Let the acceleration is a and the tension in the string is T.
Use Newton's second law
Answer:
x+4=12
x in this equation would be 8
Answer:
x=-79/4, y=-45/8. (-79/4, -45/8).
Step-by-step explanation:
-2x+4y=17
3x-10y=-3
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3(-2x+4y)=3(17)
2(3x-10y)=2(-3)
----------------------
-6x+12y=51
6x-20y=-6
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-8y=45
y=45/-8=-45/8
3x-10(-45/8)=-3
3x+450/8=-3
3x+225/4=-3
3x=-3-225/4
3x=-12/4-225/4
3x=-237/4
x=(-237/4)/3
x=(-237/4)(1/3)
x=-237/12=-79/4
Answer:
1020 seconds
Step-by-step explanation:
take the time of how long getting home to when food will be done which is 17 minutes
times that by 60 to get seconds and its 1020