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alex41 [277]
3 years ago
12

A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B. The rest of

the class did not vote. Which expression gives the percent of voters who voted for Candidate A?
Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
40  students
12-A
18-B 
40-12=28
28-18=10
10/40 did not vote.
25% did not vote
10 is one fourth of 40
fourth of 100% is 25%
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I need help on this question
deff fn [24]

Answer:

C

Step-by-step explanation:

ITS ALWAYS C UWU

6 0
3 years ago
find the length of the side of square with an area of 121 in2. A.484 in, B.30.25 in, C.11 in, D.6.5 in
marishachu [46]
For a square, the area is the square of the side length (length x width = area, but in a square length = width). That means the side length is the square root of the area.

In this case the side length is the square root of 121, which is 11. Answer is C.
3 0
3 years ago
Read 2 more answers
This is all it gave me 6 C 2 = a0
frozen [14]

Answer:

\binom{6}{2} = a_{0}=15

Step-by-step explanation:

\binom{6}{2} = a_{0}

\binom{n}{r} =\frac{n!}{r!\times(n-r)!}

It is representing a combination form where, n is number of items we have and r is the number of items we choose from n

Here, n = 6 , r = 2

\binom{6}{2} =\frac{6!}{2!\times(6-2)!}

==\frac{6!}{2!\times(4)!}

n!=n\times(n-1)\times(n-2)\times(n-3).....\times3\times2\times1

=\frac{6\times5\times4!}{2\times(4)!}

=\frac{6\times5}{2}

={3\times5}

={15}=a_0

Thus, \binom{6}{2} = a_{0}=15





8 0
3 years ago
Your friend earns $10.50 per hour. This is 125% of her hourly wage last year. How much did your friend earn per hour last year?
qwelly [4]
Well 
10.50 / 125%=8.4
your friend earned $8.40 per hour last year
8 0
3 years ago
1. What is (f⋅g)(x)?
nekit [7.7K]

Answer:

(f⋅g)(x)= x^7 + 9x^4 - 9x^3 -81

(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10

Step-by-step explanation:

For the first part of the question we have two functions

f(x) = x^4 -9

g(x) = x^3 + 9

If the expression refers to the multiplication of f and g, then:

(f⋅g)(x)= f (x)g(x)

So we multiply the function f(x) with the function g(x)

(f⋅g)(x)= (x^4 - 9)(x^3 + 9)

(f⋅g)(x)= x^7 + 9x^4 - 9x^3 -81

For the second part we have the functions:

f(x) = x^3 -2x^2 + 12x - 6\\\\g(x) = 4x^2 - 6x + 4

We wish to find (f - g) (x). We know that

(f - g)(x) = f(x) - g(x)\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 - [4x^2 - 6x + 4]\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 -4x^2 + 6x - 4

(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10

5 0
3 years ago
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