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Ivenika [448]
3 years ago
7

Assume that the probability of a driver getting into an accident is 6%, the average cost of an accident is $16,586.05, and the o

verhead cost for an insurance company per insured driver is $100. What should be this driver's insurance premium?
A. $1276.27
B. $1095.16
C. $1156.43
D. $1166.91
Mathematics
1 answer:
OLEGan [10]3 years ago
3 0
If p = 0.06 represents the probability that a customer will suffer an accident, and each accident costs the insurance company an average of $ 16,586.05.   Then, the expected value of the cost that the insurance company must pay for each driver is:
 $ 16,586.05 * 0.06 = 995,163. This plus the general cost of an insurance company per insured driver that is $ 100 gives a total of $ 1095,163. The answer is option B. The insurance company must request a premium of $ 1095.16
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Need some help with this​
Katen [24]

Answer:

1/3

Step-by-step explanation:

Slope is rise over run

your rise is 1 (because you only go up one block each time)

your run is 3 ( because you go right three times)

so 1/3

3 0
2 years ago
Help please
Digiron [165]

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

            = x² + [-(i)²√(13)²]  [Since i = √(-1)]

            = x² - (i√13)²

            = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

7 0
2 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHR/BEST ANSWER. <br><br> sorry for the screen
damaskus [11]

Answer:

The answer is A I just looked it up on mathaway and it is never wrong

Step-by-step explanation:

Standard form always has the largest coefficients first

7 0
3 years ago
Read 2 more answers
david ran on a straight track. every time he ran 480m, he took a break. After 2 breaks, he still had to run 120 m to complete th
kipiarov [429]

Answer:

The distance of the playground is 540m

Step-by-step explanation:

Here, we are interested in calculating the length of the playground given the information in the question.

Where to attack the question from is the segment that states that he took a break after 480m and also had 2 breaks. Thus, the distance traveled would be 480 * 2 = 960 m

Now, to find the length of the track, we add the distance covered plus the distance uncovered. Mathematically that would be 960m + 120m = 1,080m

In the last part of the question, we are told that the track is twice as long as the playground. This means that the length of the playground or the distance of the playground is 1080/2 = 540 m

4 0
3 years ago
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