Part A
Since order matters, we use the nPr permutation formula
We use n = 12 and r = 8

There are a little under 20 million different permutations.
<h3>Answer: 19,958,400</h3>
Side note: your teacher may not want you to type in the commas
============================================================
Part B
In this case, order doesn't matter. We could use the nCr combination formula like so.

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.
-----------------
Another way we can compute the answer is to use the result from part A.
Recall that:
nCr = (nPr)/(r!)
If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320
So,

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.
-----------------
<h3>Answer: 495</h3>