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Juliette [100K]

2 years ago

9

The following angle measures could form a triangle

1 answer:

qaws [65]2 years ago

8 0

Answer:

They don't form a triangle because all triangles degrees have to add up to 180 if you add them all up its 190 so no they don't form a triangle.

Step-by-step explanation:

84+75+31=190

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(3x-3)° [6{x-10)]° what is the value of x

DerKrebs [107]

Solve for x over the real numbers:18 ° (x - 1) (x - 10 ° x) = 0
Divide both sides by 18 °:(x - 1) (x - 10 ° x) = 0
Split into two equations:x - 1 = 0 or x - 10 ° x = 0
Add 1 to both sides:x = 1 or x - 10 ° x = 0
Collect in terms of x:x = 1 or (1 - 10 °) x = 0
Divide both sides by 1 - 10 °:Answer: x = 1 or x = 0

4 0

3 years ago

Read 2 more answers

Which is a true statement? A. –3.62 < –3.5 B. 0.8 > 7.1 C. 6.25 < 6.2 D. –3.4 > –3.3

Troyanec [42]

A is correct :)

Hope this helps!

3 0

2 years ago

What are the solutions of x^2-4x+5=0

Gnoma [55]

Answer:

Factor {x}^{2}-4x-5x

2

−4x−5.

(x-5)(x+1)=0(x−5)(x+1)=0

2 Solve for x.

x=5,-1x=5,−1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How 2 do?<br><br> (n)(n+7)(n+8)

madreJ [45]

Answer:

$n^{3} + 15n^{2} + 56n$

Step-by-step explanation:

First FOIL (n + 7)(n + 8) and then distribute n

(n + 7)(n + 8) = $n^{2} +15n + 56$

n ( $n^{2} +15n + 56$ )

= $n^{3} + 15n^{2} + 56n$

6 0

2 years ago

he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours

almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 540, \sigma = \sqrt{625} = 25$

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{569 - 540}{25}$

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

8 0

1 year ago