I believe the answer is, not positive though
(-30m+33)
Y(x-1)=z divide both sides by y
x-1=z/y add 1 to both sides
x=(z/y)+1 or more neatly
x=(z+y)/y
Answer:
6
Step-by-step explanation:
Typically these kinds of problems are solved using Venn Diagram.
Let’s solve it differently.
Here, we add the individual subject students and subtract the dual subject students and then add the triple subject students that would give us the count of all the students. If that’s more than number of students then there’s something wrong with the given data. If that’s exactly equal to number of students then all the students have taken some course(s) or the other. If that’s less than number of students then subtracting this from number of students would give us the count of students having not taken any course(s).
Thus, the count of students having taken some courses or the other is:
20+18+16–7–7–9+3 = 57–23
= 34
Subtracting it from 40 gives us 6, which is the count of students not taking any course(s).
Please mark brainliest if possible and have a nice day. :)
If you mean lowest common mutiple, then the answer is 72.
18×4=72
24×3=72
