All categories

3 years ago

Please help!! Problem in picture

Mathematics

1 answer:

notsponge [240]3 years ago

3 0

20.if m <6=72, then m < 7=108
21. if m<8,then m<7=80
22.if m<110,then m<6=90
23.if m<123, then m<8=123
24.if m<142, then m<7=38
25.if m<13, then m<8=167
26.if m<170, then m<10
27.if m<26, then m <154
,

You might be interested in

If square ABCD with side length of 7 units is reflected over the line y=x, what is length A'B'?

Art [367]

Answer:

Step-by-step explanation:

Reflection is a rigid transformation, so the side length does not change.

A'B' = 7

5 0

3 years ago

What is f(5)? I have 20 min left

jolli1 [7]

To find f(5), just look at the table and find the value for x that corresponds with f(5). In this case, this value is -1.

So, your answer is B. -1.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Patrick has decided to open a simple

Aleonysh [2.5K]

Answer:

9700

lkjhgyfdfdfffffffff nnnnn

4 0

3 years ago

1) A taxi charges $1.80 plus $0.40 per mile, m. Write an equation and solve to determine the number

Anettt [7]

the answer : 1.80x+0.40=$13

5 0

3 years ago

Read 2 more answers

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago