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emmainna [20.7K]
3 years ago
11

2.943 × 10-² (negative 2nd power) what is the quotient

Mathematics
2 answers:
Leni [432]3 years ago
8 0
2.943 × 10-²

= <span>2.943
----------
    10²</span>
lesya692 [45]3 years ago
4 0
2.943 * 10-² = <span>2.943 
20char limit
 </span>
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Glven the line segment RT, with endpolnt R(6,9) and<br> midpoint A(-3,7)
Rzqust [24]
It would be (-12, 5)
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3 years ago
Samuel saved some money for a new phone, but then he spent $24 of his savings on a
Goryan [66]

Answer:

213$

Step-by-step explanation:

24$ on headphones

189$ left

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2 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
What is the solution to the system of equations below? 3x+4y-2z=-1 -x+6y+2z=7 4x-2y+3z=27
matrenka [14]

Answer:

(3x+4y-2z=-1)= x=-1/3-4/3y+2/3z

(-x+6y=2z)= x=-7+6y=2z

(4x-2y+3z=27)= x=27/4+1/2-3/4z

Step-by-step explanation:

6 0
2 years ago
Please help!!
S_A_V [24]

Answer:

50

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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