Answer:
yes.......................
Step-by-step explanation:
Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
Hey, using y2-y1/x2-x1 you know that slope has to be -1/4
Answer:
x = y/2 - 1/2
Step-by-step explanation:
you can use the slope-intercept form of a line first, then change to terms of 'x'
y = mx + b where 'm' is the slope and 'b' is the y-intercept
if we use two points on the line, such as (-1, -1) (0, 1), we can find the slope
m = 1-(-1) / 0-(-1)
m = 2/1
b = 1
Slope-Intercept form: y = 2x + 1
in terms of 'x':
2x = y - 1
x = y/2 - 1/2
Answer:
Step-by-step explanation:
it is D=R/2T
