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4 years ago

6

James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough becaus

e he should specify that
a circle includes its diameter
the set of points is in a plane
a circle includes its radius
the set of points are collinear

2 answers:

vlabodo [156]4 years ago

6 0

The sped of points is in a plane

postnew [5]4 years ago

5 0

Answer:

The Set Of Points is In a Plane

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-7 + 4(n-1). Use this and plug in 10 for n, making it

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2 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

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3 years ago

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3 years ago

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Andreyy89

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Step-by-step explanation:

I don’t know exactly what you’re asking but here you go

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3 years ago

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Please help. 7. 2 × 5. 28

mr_godi [17]

Answer:

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Step-by-step explanation:

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2 years ago

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