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NISA [10]
3 years ago
8

How do you find the equation to 1/3 of 27?

Mathematics
1 answer:
NeX [460]3 years ago
8 0
To find 1/3 of 27 divide 27 by the denominator (which in this case would be 3) then multiply by the numerator (which is one) so you'd do 27 divided by 3 then multiply by 1
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Bridget, June and Colin share £88 in a ratio 3:3:2. How much money does each person get?
astra-53 [7]

Answer

33,33 and 22

Step-by-step explanation:

4 0
2 years ago
This right rectangular prism is filled with 1/3 -foot unit cubes.
Alex Ar [27]

Answer:

you could just count them

8 0
3 years ago
Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.​
mart [117]

Answer:

35 and 36

Step-by-step explanation:

To solve this problem, we must interpret it line by line;

  • We are dealing with consecutive integers; these are integers with a difference of 1 between them.

   let the first number = x

               second number  = x + 1

  • one - fifth of first;

             \frac{1}{5}x

  •   one - ninth of the second;

            \frac{1}{9}(x + 1)

for the "less" ;

         \frac{1}{5}x -  \frac{1}{9}(x + 1) = 3

Multiply through by 45

       45(\frac{1}{5}x) - (45) \frac{1}{9}(x + 1) = 3 x 45

           9x - 5(x + 1) = 135

           9x - 5x -5 = 135

             4x = 135 + 5

              4x = 140

                x = 35

Now, x+1  = 35 + 1 = 36

The consecutive integers are 35 and 36

4 0
3 years ago
Which is the best estimate for the quotient of 198.32 ÷ 9.001?
Whitepunk [10]
I would believe it to be 22
4 0
3 years ago
Read 2 more answers
Find integra of xlnxdx
Mademuasel [1]

Answer:

\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

\displaystyle \int x \ln x \:\: \text{d}x

To integrate the given integral, use Integration by Parts:

\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}

\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}

\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2

Therefore:

\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}

Learn more about integration here:

brainly.com/question/27805589

brainly.com/question/27983581

brainly.com/question/27759474

5 0
2 years ago
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