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PilotLPTM [1.2K]
4 years ago
11

Explain why the sum or product of rational numbers is rational; why the sum of a rational number and an irrational number is irr

ational; and why the product of a nonzero rational number and an irrational number is irrational. You can do this by providing examples of each
Mathematics
1 answer:
Colt1911 [192]4 years ago
4 0

Answer:

Rational numbers are fractional numbers, whose numerator and denominator are integers and the denominator is ever zero.

Step-by-step explanation:

The sum of rational numbers gives a rational number;

   \frac{1}{3}  + \frac{1}{3} = \frac{2}{3} , because the evaluation of the denominator always results to a non-zero integer.

The product of  \frac{1}{3} x \frac{1}{3} = \frac{1}{9}, which multiply both numerator and denominator to give integer numbers.

The sum and product of rational and irrational numbers are always irrational numbers, for instance,

           \frac{1}{3} x 7 = 2.3 , which is a number which decimal points that can only be represented by the product irrational number and rational number , where 7 is an irrational number.

       \frac{1}{3} + 7 =  7\frac{1}{3} , which is a whole number and fractional number combined.

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WILl GIVE BRAINLIEST IF YOU SHOW THE STEPS!!!
True [87]

Answer:

\frac{9x}{y^3}

Step-by-step explanation:

\frac{\left(3x^2y^4\right)^3}{3x^5y^{15}}

(3x^2y^4)^3 : 3^3x^6y^1^2

= \frac{3^3x^6y^{12}}{3x^5y^{15}}

\frac{3^{3} }{2} = 3^{2}

= \frac{3^2x^6y^{12}}{x^5y^{15}}

= \frac{x^{6} }{x^{5} } : x

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=  \frac{y^{12} }{y^{15} } : \frac{1}{3{y} }

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7 0
3 years ago
Words to match the expression 36÷4
lbvjy [14]
You set up your long division and you can multiply 4x9 to get 36 and 36-36=0 your welcome!
3 0
3 years ago
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The amount of candy left in a Halloween bucket is given by the function A(t) = 50(0.8)t where t stands for the number of minutes
natulia [17]
I think that equation is supposed to look like this:
A(t)=50(.8) ^{t}
The reason I say that is because this is an exponential decay problem, with a starting amount of 50 pieces of candy.
If that's the case, then it would look like this with a t value of 5:
A(5)=50(.8) ^{5}
and A(5)=50(.32768)
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3 years ago
Write the absolute value inequality in the form
yawa3891 [41]

Answer:

\large\boxed{|x+7|\geq2}

Step-by-step explanation:

Look at the picture.

|x-a|\geq b\\\\a=\dfrac{-9+(-5)}{2}=\dfrac{-14}{2}=-7\\\\b=-9-(-7)=-9+7=-2\\b=-5-(-7)=-5+7=2\\\\|x-(-7)|\geq2\\\\|x+7|\geq2\\\\Check:\\\\|x+7|\geq2\iff x+7\geq2\ \vee\ x+7\leq-2\qquad\text{subtract 7 from both sides}\\\\x+7-7\geq2-7\ \vee\ x+7-7\leq-2-7\\\\x\geq-5\ \vee\ x\leq-9\qquad CORRECT\ :)

4 0
4 years ago
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