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Iteru [2.4K]
3 years ago
9

At the sewing store, Debbie bought a bag of mixed buttons. She got 60 buttons in all. 30 of the buttons were large. What percent

age of the buttons were large?
Mathematics
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

Half of the persentage were large.

Step-by-step explanation:

So if you do 60 divided by 2, which is 30, and 30 of the buttons are large, then half of 60, (30) are large

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5/10 + 8/100= ? <br> 13/100, 40/100, 58/100, 6/10
Nesterboy [21]

Answer:

58/100

Step-by-step explanation:

The first step is to make the two fractions have a common denominator. 5/10=50/100. Now you can add the two fractions together. 50/100+8/100=58/100. Hope this helps!

5 0
3 years ago
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22. MULTIPLE CHOICE What number is 0.02% of 50? (Skills Review Handbook) (A) 0.01 (B) 0.1 (C) 1 (D) 100
emmainna [20.7K]

Answer:

x = 1

Then the answer is C

Step-by-step explanation:

1) Set a linear equation

\frac{2}{100}  =  \frac{x}{50}

2) Cross multiply

100x = 2 \times 50

3) Multiple the right side

100x = 100

4) Divide both side by 2

\frac{100x}{100}  =  \frac{100}{100}

5) Solving the linear equation

x = 1

The answer is (C)

7 0
2 years ago
A man walked steadily from 11.00am to 2.30pm at 5 kilometres per hour. how far did he walk
DerKrebs [107]
Taken time is from 11.00 am to 2.30 pm (14.30) = 14.30 - 11 = 3.30 hours

We know that D = S* T (D - distance, S - speed , T- time)

So, D= \frac{5km}{h}*3.5h=\boxed {17.5 hours}
5 0
3 years ago
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The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the
Viktor [21]

Answer:

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

7 0
4 years ago
OAB is a sector of a circle <br>what is the area of the sector
oee [108]

Answer:

12.56 square cm

Step-by-step explanation:

Central \:angle \:(\theta) = 40°\\Radius \: (r) = 6 cm

Let A be the area of the sector of circle.

\therefore \: A =  \frac{\theta }{360 \degree}  \times \pi {r}^{2}  \\  \\=  \frac{ 40 \degree}{360 \degree}  \times 3.14\times {6}^{2}  \\  \\    =   \frac{ 1}{9}  \times 3.14 \times  36 \\  \\  =   3.14 \times 4 \\ \\ = 12.56 \:  {cm}^{2}

6 0
3 years ago
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