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3 years ago

5

Bob can paint a fence in 12 hours, and working with Jen can paint a fence in 4 hours. How long would it have taken Jen to paint

the fence alone?

1 answer:

butalik [34]3 years ago

8 0

Answer:

6 hours

Step-by-step explanation:

For Bob

12 hours = 1 fence

1 hour = 1/12 fence

Together Bob and Jen

4 hours = 1 fence

1 hour = 1/4 fence

Now, for Jen:

1 hour = 1/4 - 1/12= 3/12 - 1/12 = 2/12=1/6

Find the amount of time Jen will need:

1/6 fence = 1 hour

1 fence = 6 hour

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Hey guys, I am about to start studying for a math test happening in two weeks about statistics and I am wondering if you guys ha

Stels [109]

Answer more questions on every topic you’ve been thought. Answer research questions and questions likely to come out in the exam. Dwell on what you are trying to know more that what you already know. A planner could help as well and the Good God would help you

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2 years ago

Can someone please show me how<br><br> 19169000*e^(0.15)= 222712201<br><br> When e= 2.7182818284?

Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

$x =19 169 000 \times e^{0.15}$

(a) The direct method

$x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201$

(b) The indirect method

$\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201$

8 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

EFV and EDW are straight lines.<br>Find the value of x and of y.

Makovka662 [10]

Answers:

x = 72

y = 83

============================================================

Explanation:

Angle VFG is 50 degrees. The angle adjacent to this is angle EFG which is 180-50 = 130 degrees.

Angle HDW is 77 degrees. The supplementary angle adjacent to this is 180-77 = 103 degrees which is angle EDH.

Pentagon EFGHD has the following five interior angles

E = x
F = 130
G = 170
H = 65
D = 103

Note that angles F = 130 and D = 103 were angles EFG and EDH we calculated earlier.

For any pentagon, the interior angles always add to 180(n-2) = 180(5-2) = 180*3 = 540 degrees.

This means,

E+F+G+H+D = 540

x+130+170+65+103 = 540

x+468 = 540

x = 72

---------------------------------------

Now focus your attention on triangle THS

We see that the interior angles are

T = y
H = 65
S = 32

The angle H is 65 degrees because it's paired with the other 65 degree angle shown. They are vertical angles.

For any triangle, the angles always add to 180

T+H+S = 180

y+65+32 = 180

y+97 = 180

y = 180-97

y = 83

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3 years ago

(3x²+4x-1) + (-2x²-3x+2)

Vedmedyk [2.9K]

Answer:

(3x²+4x-1) + (-2x²-3x+2)

3x²+4x-1 -2x²-3x+2

3x²-2x²+4x-3x-1+2

x²+x+1

5 0

3 years ago

Read 2 more answers