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hoa [83]
3 years ago
15

Ji and jl are opposite rays

Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0
What exactly are you looking for? you gave us no question to answer lol
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A ratio of boys to girls in the classroom is 4 to 5 if there are 20 girls how many boys would there be
Viktor [21]

Answer:

16 to 20

Step-by-step explanation:

Let's do our math.

4 to 5

8 to 10

12 to 15

16 to 20

In order to get to 20, you'd have to multiply 5 by 4. So in order to get an equal ratio, you multiply 4 by 4 and get 16.

I hope this helps!

-No one

8 0
2 years ago
4. 20% of what<br> number is 6?
n200080 [17]

Answer:

30

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What would the equation be of the relationship??
Brums [2.3K]
I don’t really know that
6 0
3 years ago
in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0
3 years ago
What is the answer to 3(m-1)=5m +3 - 2m
notsponge [240]
Is there a answer for m what is m
5 0
3 years ago
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