Mercury can be obtained by reacting mercury(II) sulfide with calcium oxide. How many grams of calcium oxide are needed to produc
e 42.0 g of Hg? 4HgS(s) + 4CaO(s) ---> 4Hg(l) + 3CaS(s) + CaSO4. please show all the work
1 answer:
The number of grams of Ca) needed to produce 42.0 g of Hg is calciulated as below
4 HgS + 4CaO = 4 Hg + 3 Cas +CaSO4
calculate the moles of Hg produced
moles=mass/molar mass
moles of Hg = 42 g/200.59 g/mole = 0.2094 moles
by use of mole ratio of Cao:Hg which is 4:4 the moles of CaO = 0.2094 x4/4 =0.2094 moles
mass of CaO=moles x molar mass of CaO
mass of caO=0.2094 x56 = 11.73 grams
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