Idk how to write the formula I had this same question
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O
To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side.
To start off, you wanna know the number of atoms in each element on both sides, so take it apart:
[reactants] [product]
Na- 1 Na- 2
N- 1 N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)
O- 4 O- 7 (same reason as above)
Pb- 1 Pb- 1
Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2:
2NaNO3
Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become:
Na- 2 Na- 2
N- 2 N- 2 (it balanced out)
O- 7 (coefficient times subscript, plus lone O) O- 7 (balanced out)
Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything).
Now to put it back together, it will look like this:
2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
18 moles of water are produced in the above reaction.
Hope this helps you!
<u>Answer:</u>
<u>For A:</u> The 
for the given reaction is 
<u>For B:</u> The 
for the given reaction is 1642.
<u>Explanation:</u>
The given chemical reaction follows:
The expression of for the above reaction follows:
We are given:
Putting values in above equation, we get:
Hence, the for the given reaction is
Relation of with is given by the formula:
where,
= equilibrium constant in terms of partial pressure =
= equilibrium constant in terms of concentration = ?
R = Gas constant = 
T = temperature = 500 K
= change in number of moles of gas particles = 
Putting values in above equation, we get:
Hence, the for the given reaction is 1642.
Answer:it is sterilized in the process
Explanation:
