Answer is: pH of ammonium hydroxide is 11.13.
Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ +
OH⁻<span>.
</span>
Kb(NH₄OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₄OH<span>) = 0.1 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = x.
c(</span>NH₄OH<span>) = 0.1 M- x.
Kb = c(NH</span>₄⁺) · c(OH⁻) / c(NH₄OH<span>).
0,000018 = x² / 0.1 mol/L - x</span>.
Solve quadratic equation: x = c(OH⁻) = 0.00133 M.
pOH = -logc(OH⁻).
pOH = 2.87.
pH = 14 - 2.87.
pH = 11.13.
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Answer:
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Answer:
rate= k[A]²[B]²[C]
Explanation:
When concentration of A is increased two times ,keeping other's concentration constant , rate of reaction becomes 4 times .
So rate is proportional to [A]²
When concentration of B is increased two times , keeping other's concentration constant,rate of reaction becomes 4 times.
So rate is proportional to [B]²
When concentration of C is increased two times , keeping other's concentration constant, rate of reaction becomes 2 times.
So rate is proportional to [C]
So rate= k[A]²[B]²[C]
