Step-by-step explanation:
LHS=(1-sin60)/cos60
=(1-√3÷2)/1÷2
=2(1-√3÷2)
=2-√3
RHS=(1-tan30)/(1+tan30)
={1-(1÷√3)}/{1+(1÷√3)}
={(√3-1)/√3}/{(√3+1)/√3}
=(√3-1)/(√3+1)
={(√3-1)(√3-1)}/{(√3+1)(√3-1)}
=(3-√3-√3+1)/(3-1)
=(4-2√3)/2
=2-√3
Therefore LHS=RHS
Answer:
A.
Step-by-step explanation:
Graph B must be incorrect as this is a directly proportional relationship. Likewise, graph C shows an inversely proportional relationship.
Between graph A and D, only graph A passes through the origin, which is true because if length is zero, perimeter is zero.
Hence the answer is Graph A.
B. 10 years, 5% APR
it’s telling me to type more words so ignore this part.
Can you get a better shot of the problem?
