1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SOVA2 [1]
3 years ago
7

Elapsed time five in the afternoon to 1 minute after midnight​

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

The elapsed time is 7hrs and 1 minute.

You might be interested in
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Billy went on the Yahoo Finance website to check the value of his investment. Yesterday his stock was worth
maxonik [38]

Answer:

The investment decreased by 16.5771% per share.

Step-by-step explanation:

7 0
3 years ago
What is the answer plz help
ss7ja [257]

Answer:

x=82

Step-by-step explanation:

8 0
3 years ago
The altitude of an airplane
kirill [66]

Answer:

it depends

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Probability theory predicts that there is a 16.2% chance of a particular basketball player making 5 free throws in a row. If the
kenny6666 [7]
There is a 83.8% chance that the player will have at least 1 missed free throw.
5000 · 0.838 = 4190 simulations
6 0
3 years ago
Read 2 more answers
Other questions:
  • i bought 1 sandwich and 2 sodas for $5.50. A sandwich cost $1.00 more than a soda . How much did the sandwich cost ?
    8·1 answer
  • Based on the following graph, what is the most enjoyed candy and what is the approximate level of enjoyment?
    11·2 answers
  • A rectangular prism has a length of 8 in., a width of 4 in., and a height of 214 in.
    6·1 answer
  • Find the difference:
    11·1 answer
  • 17 = X + 3 HELPPPP FAST
    14·2 answers
  • 5.solve for x. 6.solve for x.
    6·1 answer
  • 4 sisters love barrettes. they have a value pack that contains 92 barrettes. how many barrettes can each sister have if they sha
    10·2 answers
  • Which polynomial best represents the expression
    8·2 answers
  • Please help me asap
    12·2 answers
  • Can someone pls help me I'm stuck o these two questions
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!