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labwork [276]
3 years ago
11

bob left work and traveled to school at an average speed of 25 mph. if it took bob 35 minutes to reach school, how far is bobs s

chool from his place of work
Mathematics
1 answer:
Alchen [17]3 years ago
8 0
Rate x time = distance
25   x  35/60 = distance  (35/60 is 35 minutes out of an hour- 60 minutes)
25/1 x 7/12  = distance (I put the 25 over 1 and reduced 35/60)
175/12 ≈ 14.58 miles

Notice that the time had to be in a fraction of an hour in order to do this.
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new vintage 1965 convertible requires an ol change every 400 miles and replacement of all fBuids every 13,000 mles If these serv
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Answer: There are 26000 miles that will both be due at the same time.

Step-by-step explanation:

Since we have given that

Number of miles required by new vintage = 400

Number of miles if these services have must been performed by the dealer = 13000

We need to find the number of miles from now that will both be due at the same time.

We would use "LCM of 400 and 13000":

As we know that LCM of 400 and 13000 is 26000.

So, there are 26000 miles that will both be due at the same time.

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3 years ago
Sofia purchased a new car in 2007 for$34,000. The value of the car has been depreciating exponentially at a constant rate. If th
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Answer:

$7,718

Step-by-step explanation:

Given that :

Cost of car in 2007 = $34000

Cost of car in 2014 = $16200

Predicted value of car in 2021

Lets obtain the percentage Depreciation (d) :

Worth (A) of car in 2014 = $16200

Time (t) = 2014 - 2007 = 7 years

Initial cost (I) = price in 2007

A = I(1 - d/100)^7

16200 = 34000( 1 - d/100)^7

16200 = 34000(1 - 0.01d)^7

(16200/34000)^1/7= 1 - 0.01d

0.8995 = 1 - 0.01d

0.01d = 1 - 0.8995

d = 0.1005 /0.01

d = 10.05

Value of car in year 2021:

t = 2021 - 2007 = 14 years

A = I(1 - 10.05/100)^14

A = 34000(1 - 0.1005)^14

A = 34000(0.8995)^14

A = 34000 * 0.2269950

A =7717.83100

Approximate worth = $7718

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