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labwork [276]
3 years ago
11

bob left work and traveled to school at an average speed of 25 mph. if it took bob 35 minutes to reach school, how far is bobs s

chool from his place of work
Mathematics
1 answer:
Alchen [17]3 years ago
8 0
Rate x time = distance
25   x  35/60 = distance  (35/60 is 35 minutes out of an hour- 60 minutes)
25/1 x 7/12  = distance (I put the 25 over 1 and reduced 35/60)
175/12 ≈ 14.58 miles

Notice that the time had to be in a fraction of an hour in order to do this.
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Cos 157.5º=-cos (180º-157.5º)=-cos 22.5=-cos(45/2)

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In this case 157.5º is in the second quadrant, therefore we use the following equation:
cos Ф/2=-√((1+cosФ)/2).          (we will have a negative number)

cos 157.5º=-cos (45/2)=-√((1+cos 45º)/2)
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Answer: cos 157.5º= -√(2+√2) / 2

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