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3 years ago

3. Marilyn purchased 400 shares of stock for $22.75 per

Mathematics

1 answer:

Mazyrski [523]3 years ago

6 0

The percent gain is 52.1%

Step-by-step explanation:

Given

Purchase price of one share = $22.75

Sale price of one share = $34.60

Total shares = 400

So,

Total purchase price of shares = 22.75*400 = $9100

Total sale price of shares = 34.60*400 = $13840

Total capital gain:

$= Sale\ price - Purchase\ price\\= 13840 - 9100\\=4740$

Percent capital gain is given by:

$Capital\ gain = \frac{Capital\ gain}{Purchase\ price} * 100\\= \frac{4740}{9100} * 100\\=0.5208*100\\=52.08$

Rounding off to nearest tenth

52.1%

Hence,

The percent gain is 52.1%

Keywords: Percentage, capital gain

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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

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(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

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(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

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3 years ago

Omar makes a total of $51.75 selling brownies and muffins at a bake sale if he sells 16 brownies for $2.25 each how many muffins

telo118 [61]

Answer:

He can make 9 Muffins

Step-by-step explanation:

16*2.25=36

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15.75/1.75=9 Divide the number you got after subtracting by by how many he is going to sell each of then

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kati45 [8]

Answer:

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